1. What is the Wavelength from Photon Energy?

The wavelength from photon energy calculation determines the wavelength of light corresponding to a given photon energy using Planck's relation. This is fundamental in quantum mechanics and optics for understanding the particle-wave duality of light.

2. How Does the Calculator Work?

The calculator uses the wavelength formula:

Where:

• \( \lambda \) — Wavelength in meters
• \( h \) — Planck's constant (6.62607015 × 10⁻³⁴ J·s)
• \( c \) — Speed of light (299,792,458 m/s)
• \( E \) — Photon energy in joules

Explanation: The formula relates the energy of a photon to its wavelength through fundamental physical constants, demonstrating the inverse relationship between energy and wavelength.

3. Importance of Wavelength Calculation

Details: Calculating wavelength from photon energy is crucial in spectroscopy, quantum mechanics, optical engineering, and understanding electromagnetic radiation properties across different energy ranges.

4. Using the Calculator

Tips: Enter photon energy in joules. The calculator will compute the corresponding wavelength in nanometers. Energy must be greater than zero for valid results.

5. Frequently Asked Questions (FAQ)

Q1: What is the relationship between energy and wavelength?
A: Energy and wavelength have an inverse relationship - higher energy photons have shorter wavelengths, and lower energy photons have longer wavelengths.

Q2: What are typical photon energy ranges for visible light?
A: Visible light photons have energies between approximately 1.65 eV (red) to 3.26 eV (violet), corresponding to wavelengths of 380-750 nm.

Q3: How do I convert electron volts to joules?
A: Multiply electron volts by 1.602 × 10⁻¹⁹ to convert to joules (1 eV = 1.602 × 10⁻¹⁹ J).

Q4: Can this calculator determine color from wavelength?
A: Yes, the calculated wavelength corresponds to specific colors in the visible spectrum, though perception may vary based on intensity and context.

Q5: What are the limitations of this calculation?
A: This assumes photons in vacuum and doesn't account for medium effects, relativistic corrections, or quantum mechanical considerations for extremely high energies.