Home
Back
Acceleration Due To Gravity In Feet:
| From: | To: |
The acceleration due to gravity in feet per second squared (ft/s²) is the standard gravitational acceleration used in the imperial system. The standard value is 32.174 ft/s², which represents the acceleration experienced by objects in free fall near the Earth's surface when measured in feet.
The calculator uses the fundamental physics formula:
Where:
Explanation: This calculation converts mass to weight by multiplying by the standard gravitational acceleration in the imperial system.
Details: Understanding gravitational acceleration in feet is crucial for engineering calculations, structural design, physics experiments, and any application using imperial units where gravitational forces need to be considered.
Tips: Enter mass in pounds (lb) to calculate the corresponding weight force in pound-force (lbf). The calculator uses the standard gravitational acceleration of 32.174 ft/s².
Q1: Why is gravity 32.174 ft/s²?
A: This value is derived from the metric standard of 9.80665 m/s² converted to feet per second squared (1 meter = 3.28084 feet).
Q2: What is the difference between lb and lbf?
A: Pound (lb) is a unit of mass, while pound-force (lbf) is a unit of force. One pound-force is the force required to accelerate one pound mass at 32.174 ft/s².
Q3: Does gravity vary by location?
A: Yes, gravitational acceleration varies slightly with latitude, altitude, and local geology, but 32.174 ft/s² is the standard value used for most calculations.
Q4: When is this calculation important?
A: This calculation is essential in structural engineering, mechanical design, physics problems, and any scenario where weight forces need to be determined from mass in imperial units.
Q5: Can this be used for other planets?
A: No, this calculator uses Earth's standard gravity. Other planets have different gravitational accelerations that would require different values.